For the equationAnswer the following based on beginning the reaction with 2.92 g N and 9.95 g O and recovering 8.32 g of NO at the end of the reaction.

 For the  equationAnswer the following based on beginning the reaction with 2.92 g N and 9.95 g O and recovering 8.32 g of NO at the end of the reaction. Enter the coeffiecients () from your balanced equation. If your balanced equation were H + O → HO, you would enter )     (Tol: ± 0)   Mass of NO possible from N     (Tol: ± 0.1)   Mass of NO possible from O     (Tol: ± 0.1)   Mass of the reactant present in excess after the reaction is complete ().     (Tol: ± 0.05)   Theoretical Yield of NO     (Tol: ± 0.1)   % Yield NO     (Tol: ± 0.1)